en.wikipedia.org/wiki/Fourier-transform_infrared_spectroscopy
2 corrections found
For rapid calculation the number of points in the interferogram has to equal a power of two.
This is outdated: FFT algorithms do not require power-of-two input lengths. Power-of-two sizes can be faster, but arbitrary lengths are routinely supported.
Full reasoning
This statement presents a power-of-two length as a requirement, but modern FFT implementations do not require that.
The core mathematical task here is a discrete Fourier transform (DFT). Well-established FFT libraries compute DFTs for arbitrary lengths, including prime sizes. For example, the official FFTW documentation states that "the input data can have arbitrary length" and that FFTW uses O(n log n) algorithms "for all lengths, including prime numbers." Its reference manual also says of the transform size n: "It can be any positive integer," while noting only that powers of 2 are especially fast.
So the accurate statement is that power-of-two lengths were historically convenient for some radix-2 FFT implementations and may still be performance-optimal in many cases, but they are not required for rapid FFT-based spectral calculation in general.
2 sources
- Introduction (FFTW 3.3.10)
The input data can have arbitrary length. FFTW employs O(n log n) algorithms for all lengths, including prime numbers.
- FFTW - FFTW Reference
n is the size of the transform. It can be any positive integer... Transforms whose sizes are powers of 2 are especially fast.
In a simple Michelson interferometer, one beam passes twice through the beamsplitter but the other passes through only once.
The pass-count here is wrong for a plate beamsplitter Michelson interferometer. Standard references state that one beam traverses the beamsplitter glass three times, while the other traverses it once.
Full reasoning
This sentence misstates the unequal glass paths in a standard Michelson interferometer that uses a plate beamsplitter.
Authoritative optics references explain that the compensator plate is needed because the two arms do not traverse the beamsplitter substrate equally: one beam goes through the beamsplitter glass three times, while the other goes through it once. OpenStax's University Physics text says, "one beam passes through M three times and the other only once," and notes that the compensator plate is added so both beams traverse the same thickness of glass. TYDEX's FTIR beamsplitter documentation gives the same explanation, stating that the compensator plate corrects for the fact that "the other beam passes through the beamsplitter plate three times instead of one."
Because both cited sources describe the unequal traversal as three versus one, the article's two versus one wording is factually incorrect.
2 sources
- 3.6: The Michelson Interferometer - Physics LibreTexts / OpenStax
Notice from the figure that one beam passes through M three times and the other only once. To ensure that both beams traverse the same thickness of glass, a compensator plate C... is placed in the arm containing M2.
- TYDEX FTIR Beam Splitter
The beam which is one time reflected from the beamsplitter ... must also pass there and back through an inclined compensator plate to compensate for the fact that the other beam passes through the beamsplitter plate three times instead of one.